Suppose you have a variable called Feedback and you want to find out if the value is 1 or 2. Does the following work?

`Feedback = 1 OR 2`

No, it first evaluates the righthand side of the expression “1 OR 2” as True. Actually 1 is True so “1 OR anything” will be true. I know that’s not what you wanted. What you wanted was

`(Feedback =1) OR (Feedback = 2)`

which produces the correct, expected result. *Caveat emptor*